1/6(a-40)=1/3(2a+4)

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Solution for 1/6(a-40)=1/3(2a+4) equation:



1/6(a-40)=1/3(2a+4)
We move all terms to the left:
1/6(a-40)-(1/3(2a+4))=0
Domain of the equation: 6(a-40)!=0
a∈R
Domain of the equation: 3(2a+4))!=0
a∈R
We calculate fractions
(3a2/(6(a-40)*3(2a+4)))+(-6aa/(6(a-40)*3(2a+4)))=0
We calculate terms in parentheses: +(3a2/(6(a-40)*3(2a+4))), so:
3a2/(6(a-40)*3(2a+4))
We multiply all the terms by the denominator
3a2
We add all the numbers together, and all the variables
3a^2
Back to the equation:
+(3a^2)
We calculate terms in parentheses: +(-6aa/(6(a-40)*3(2a+4))), so:
-6aa/(6(a-40)*3(2a+4))
We multiply all the terms by the denominator
-6aa
Back to the equation:
+(-6aa)
We get rid of parentheses
3a^2-6aa=0

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