2(x+-6)+4=4(x+2)+-12

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Solution for 2(x+-6)+4=4(x+2)+-12 equation: 



2(x+-6)+4=4(x+2)+-12

We move all terms to the left:

2(x+-6)+4-(4(x+2)+-12)=0

We add all the numbers together, and all the variables

2(x-6)-(4(x+2)+-12)+4=0

We use the square of the difference formula

2(x-6)-(4(x+2)-12)+4=0

We multiply parentheses

2x-(4(x+2)-12)-12+4=0



We calculate terms in parentheses: -(4(x+2)-12), so:

4(x+2)-12

We multiply parentheses

4x+8-12

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

2x-(4x-4)-8=0

We get rid of parentheses

2x-4x+4-8=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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