4(3n+3)=9(3n+2)+9

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Solution for 4(3n+3)=9(3n+2)+9 equation: 



4(3n+3)=9(3n+2)+9

We move all terms to the left:

4(3n+3)-(9(3n+2)+9)=0

We multiply parentheses

12n-(9(3n+2)+9)+12=0



We calculate terms in parentheses: -(9(3n+2)+9), so:

9(3n+2)+9

We multiply parentheses

27n+18+9

We add all the numbers together, and all the variables

27n+27

Back to the equation:

-(27n+27)



We get rid of parentheses

12n-27n-27+12=0

We add all the numbers together, and all the variables

-15n-15=0

We move all terms containing n to the left, all other terms to the right

-15n=15

n=15/-15

n=-1

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