2(x)+3(x+1)+4(x+2)=56

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Solution for 2(x)+3(x+1)+4(x+2)=56 equation: 



2(x)+3(x+1)+4(x+2)=56

We move all terms to the left:

2(x)+3(x+1)+4(x+2)-(56)=0

We multiply parentheses

2x+3x+4x+3+8-56=0

We add all the numbers together, and all the variables

9x-45=0

We move all terms containing x to the left, all other terms to the right

9x=45

x=45/9

x=5

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