x2+41x-2130=0

Solution for x2+41x-2130=0 equation:

x2+41x-2130=0

We add all the numbers together, and all the variables

x^2+41x-2130=0

a = 1; b = 41; c = -2130;
Δ = b2-4ac
Δ = 412-4·1·(-2130)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-101}{2*1}=\frac{-142}{2}
=-71
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+101}{2*1}=\frac{60}{2}
=30
$