2(w+2)=4(w+5/2)

Solution for 2(w+2)=4(w+5/2) equation:

2(w+2)=4(w+5/2)

We move all terms to the left:

2(w+2)-(4(w+5/2))=0

We add all the numbers together, and all the variables

2(w+2)-(4(+w+5/2))=0

We multiply parentheses

2w-(4(+w+5/2))+4=0

We multiply all the terms by the denominator


2w*2))-(4(+w+5+4*2))=0

We add all the numbers together, and all the variables

2w*2))-(4(w+13))=0

We add all the numbers together, and all the variables

2w*2))-(4(w=0

Wy multiply elements

4w^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{8}=0$