(X+2(x-10))=48

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Solution for (X+2(x-10))=48 equation: 



(X+2(X-10))=48

We move all terms to the left:

(X+2(X-10))-(48)=0



We calculate terms in parentheses: +(X+2(X-10)), so:

X+2(X-10)

We multiply parentheses

X+2X-20

We add all the numbers together, and all the variables

3X-20

Back to the equation:

+(3X-20)



We get rid of parentheses

3X-20-48=0

We add all the numbers together, and all the variables

3X-68=0

We move all terms containing X to the left, all other terms to the right

3X=68

X=68/3

X=22+2/3

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