2(w+2)-w=3(w-1)

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Solution for 2(w+2)-w=3(w-1) equation: 



2(w+2)-w=3(w-1)

We move all terms to the left:

2(w+2)-w-(3(w-1))=0

We add all the numbers together, and all the variables

-1w+2(w+2)-(3(w-1))=0

We multiply parentheses

-1w+2w-(3(w-1))+4=0



We calculate terms in parentheses: -(3(w-1)), so:

3(w-1)

We multiply parentheses

3w-3

Back to the equation:

-(3w-3)



We add all the numbers together, and all the variables

w-(3w-3)+4=0

We get rid of parentheses

w-3w+3+4=0

We add all the numbers together, and all the variables

-2w+7=0

We move all terms containing w to the left, all other terms to the right

-2w=-7

w=-7/-2

w=3+1/2

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