2b-(3-b)+4=11

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Solution for 2b-(3-b)+4=11 equation:



2b-(3-b)+4=11
We move all terms to the left:
2b-(3-b)+4-(11)=0
We add all the numbers together, and all the variables
2b-(-1b+3)+4-11=0
We add all the numbers together, and all the variables
2b-(-1b+3)-7=0
We get rid of parentheses
2b+1b-3-7=0
We add all the numbers together, and all the variables
3b-10=0
We move all terms containing b to the left, all other terms to the right
3b=10
b=10/3
b=3+1/3

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