2(w+2)-w=2(w-1)+5

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Solution for 2(w+2)-w=2(w-1)+5 equation:



2(w+2)-w=2(w-1)+5
We move all terms to the left:
2(w+2)-w-(2(w-1)+5)=0
We add all the numbers together, and all the variables
-1w+2(w+2)-(2(w-1)+5)=0
We multiply parentheses
-1w+2w-(2(w-1)+5)+4=0
We calculate terms in parentheses: -(2(w-1)+5), so:
2(w-1)+5
We multiply parentheses
2w-2+5
We add all the numbers together, and all the variables
2w+3
Back to the equation:
-(2w+3)
We add all the numbers together, and all the variables
w-(2w+3)+4=0
We get rid of parentheses
w-2w-3+4=0
We add all the numbers together, and all the variables
-1w+1=0
We move all terms containing w to the left, all other terms to the right
-w=-1
w=-1/-1
w=1

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