3(t-3)=4(2t+1)

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Solution for 3(t-3)=4(2t+1) equation:



3(t-3)=4(2t+1)
We move all terms to the left:
3(t-3)-(4(2t+1))=0
We multiply parentheses
3t-(4(2t+1))-9=0
We calculate terms in parentheses: -(4(2t+1)), so:
4(2t+1)
We multiply parentheses
8t+4
Back to the equation:
-(8t+4)
We get rid of parentheses
3t-8t-4-9=0
We add all the numbers together, and all the variables
-5t-13=0
We move all terms containing t to the left, all other terms to the right
-5t=13
t=13/-5
t=-2+3/5

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