2(w+1)+4w=3(2w-1)+1

Solution for 2(w+1)+4w=3(2w-1)+1 equation:

2(w+1)+4w=3(2w-1)+1

We move all terms to the left:

2(w+1)+4w-(3(2w-1)+1)=0

We add all the numbers together, and all the variables

4w+2(w+1)-(3(2w-1)+1)=0

We multiply parentheses

4w+2w-(3(2w-1)+1)+2=0


We calculate terms in parentheses: -(3(2w-1)+1), so:

3(2w-1)+1

We multiply parentheses

6w-3+1

We add all the numbers together, and all the variables

6w-2

Back to the equation:

-(6w-2)


We add all the numbers together, and all the variables

6w-(6w-2)+2=0

We get rid of parentheses

6w-6w+2+2=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation