(5/2)n+(1/6)n=-16/7

Solution for (5/2)n+(1/6)n=-16/7 equation:

(5/2)n+(1/6)n=-16/7

We move all terms to the left:

(5/2)n+(1/6)n-(-16/7)=0


Domain of the equation: 2)n!=0

n!=0/1

n!=0

n∈R



Domain of the equation: 6)n!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

(+5/2)n+(+1/6)n-(-16/7)=0

We multiply parentheses

5n^2+n^2-(-16/7)=0

We get rid of parentheses

5n^2+n^2+16/7=0

We multiply all the terms by the denominator


5n^2*7+n^2*7+16=0

Wy multiply elements

35n^2+7n^2+16=0

We add all the numbers together, and all the variables

42n^2+16=0

a = 42; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·42·16
Δ = -2688
Delta is less than zero, so there is no solution for the equation