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2(v-7)(-v-2)=0
We add all the numbers together, and all the variables
2(v-7)(-1v-2)=0
We multiply parentheses ..
2(-1v^2-2v+7v+14)=0
We multiply parentheses
-2v^2-4v+14v+28=0
We add all the numbers together, and all the variables
-2v^2+10v+28=0
a = -2; b = 10; c = +28;
Δ = b2-4ac
Δ = 102-4·(-2)·28
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-18}{2*-2}=\frac{-28}{-4} =+7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+18}{2*-2}=\frac{8}{-4} =-2 $
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