0.06=x*0.032*(1-x)*0.12

Solution for 0.06=x*0.032*(1-x)*0.12 equation:

0.06=x*0.032(1-x)*0.12

We move all terms to the left:

0.06-(x*0.032(1-x)*0.12)=0

We add all the numbers together, and all the variables

-(x*0.032(-1x+1)*0.12)+0.06=0


We calculate terms in parentheses: -(x*0.032(-1x+1)*0.12), so:

x*0.032(-1x+1)*0.12

Wy multiply elements

0x^2

We add all the numbers together, and all the variables

x^2

Back to the equation:

-(x^2)


We add all the numbers together, and all the variables

-1x^2+0.06=0

a = -1; b = 0; c = +0.06;
Δ = b2-4ac
Δ = 02-4·(-1)·0.06
Δ = 0.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.24}}{2*-1}=\frac{0-\sqrt{0.24}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.24}}{2*-1}=\frac{0+\sqrt{0.24}}{-2}
=\frac{\sqrt{}}{-2}
$