(25-5x)5=125+(10x-5)5

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Solution for (25-5x)5=125+(10x-5)5 equation: 



(25-5x)5=125+(10x-5)5

We move all terms to the left:

(25-5x)5-(125+(10x-5)5)=0

We add all the numbers together, and all the variables

(-5x+25)5-(125+(10x-5)5)=0

We multiply parentheses

-25x-(125+(10x-5)5)+125=0



We calculate terms in parentheses: -(125+(10x-5)5), so:

125+(10x-5)5

determiningTheFunctionDomain
(10x-5)5+125

We multiply parentheses

50x-25+125

We add all the numbers together, and all the variables

50x+100

Back to the equation:

-(50x+100)



We get rid of parentheses

-25x-50x-100+125=0

We add all the numbers together, and all the variables

-75x+25=0

We move all terms containing x to the left, all other terms to the right

-75x=-25

x=-25/-75

x=1/3

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