j2=2.3

Solution for j2=2.3 equation:

j2=2.3

We move all terms to the left:

j2-(2.3)=0

We add all the numbers together, and all the variables

j^2-2.3=0

a = 1; b = 0; c = -2.3;
Δ = b2-4ac
Δ = 02-4·1·(-2.3)
Δ = 9.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{9.2}}{2*1}=\frac{0-\sqrt{9.2}}{2}
=-\frac{\sqrt{}}{2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{9.2}}{2*1}=\frac{0+\sqrt{9.2}}{2}
=\frac{\sqrt{}}{2}
$