2(v-4)=8v+2-2(-5v-4)

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Solution for 2(v-4)=8v+2-2(-5v-4) equation: 



2(v-4)=8v+2-2(-5v-4)

We move all terms to the left:

2(v-4)-(8v+2-2(-5v-4))=0

We multiply parentheses

2v-(8v+2-2(-5v-4))-8=0



We calculate terms in parentheses: -(8v+2-2(-5v-4)), so:

8v+2-2(-5v-4)

determiningTheFunctionDomain
8v-2(-5v-4)+2

We multiply parentheses

8v+10v+8+2

We add all the numbers together, and all the variables

18v+10

Back to the equation:

-(18v+10)



We get rid of parentheses

2v-18v-10-8=0

We add all the numbers together, and all the variables

-16v-18=0

We move all terms containing v to the left, all other terms to the right

-16v=18

v=18/-16

v=-1+1/8

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