(4c+20)=(3c-15)

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Solution for (4c+20)=(3c-15) equation: 



(4c+20)=(3c-15)

We move all terms to the left:

(4c+20)-((3c-15))=0

We get rid of parentheses

4c-((3c-15))+20=0



We calculate terms in parentheses: -((3c-15)), so:

(3c-15)

We get rid of parentheses

3c-15

Back to the equation:

-(3c-15)



We get rid of parentheses

4c-3c+15+20=0

We add all the numbers together, and all the variables

c+35=0

We move all terms containing c to the left, all other terms to the right

c=-35

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