2(v-1)=8v+9-2(-6v-2)

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Solution for 2(v-1)=8v+9-2(-6v-2) equation: 



2(v-1)=8v+9-2(-6v-2)

We move all terms to the left:

2(v-1)-(8v+9-2(-6v-2))=0

We multiply parentheses

2v-(8v+9-2(-6v-2))-2=0



We calculate terms in parentheses: -(8v+9-2(-6v-2)), so:

8v+9-2(-6v-2)

determiningTheFunctionDomain
8v-2(-6v-2)+9

We multiply parentheses

8v+12v+4+9

We add all the numbers together, and all the variables

20v+13

Back to the equation:

-(20v+13)



We get rid of parentheses

2v-20v-13-2=0

We add all the numbers together, and all the variables

-18v-15=0

We move all terms containing v to the left, all other terms to the right

-18v=15

v=15/-18

v=-5/6

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