22s=16+3(5s+4

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Solution for 22s=16+3(5s+4 equation: 



22s=16+3(5s+4

We move all terms to the left:

22s-(16+3(5s+4)=0



We calculate terms in parentheses: -(16+3(5s+4), so:

16+3(5s+4

determiningTheFunctionDomain
3(5s+4+16

Back to the equation:

-(3(5s+4+16)



We add all the numbers together, and all the variables

22s-(3(5s+20)=0



We calculate terms in parentheses: -(3(5s+20), so:

3(5s+20





We calculate terms in parentheses: -(3(5s+20), so:

3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





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3(5s+20





We calculate terms in parentheses: -(3(5s+20), so:

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3(5s+20





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