2(v-1)=8v+4-4(-2v-3)

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Solution for 2(v-1)=8v+4-4(-2v-3) equation: 



2(v-1)=8v+4-4(-2v-3)

We move all terms to the left:

2(v-1)-(8v+4-4(-2v-3))=0

We multiply parentheses

2v-(8v+4-4(-2v-3))-2=0



We calculate terms in parentheses: -(8v+4-4(-2v-3)), so:

8v+4-4(-2v-3)

determiningTheFunctionDomain
8v-4(-2v-3)+4

We multiply parentheses

8v+8v+12+4

We add all the numbers together, and all the variables

16v+16

Back to the equation:

-(16v+16)



We get rid of parentheses

2v-16v-16-2=0

We add all the numbers together, and all the variables

-14v-18=0

We move all terms containing v to the left, all other terms to the right

-14v=18

v=18/-14

v=-1+2/7

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