-6(u+1)=-2(2u-3)+7u

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Solution for -6(u+1)=-2(2u-3)+7u equation: 



-6(u+1)=-2(2u-3)+7u

We move all terms to the left:

-6(u+1)-(-2(2u-3)+7u)=0

We multiply parentheses

-6u-(-2(2u-3)+7u)-6=0



We calculate terms in parentheses: -(-2(2u-3)+7u), so:

-2(2u-3)+7u

We add all the numbers together, and all the variables

7u-2(2u-3)

We multiply parentheses

7u-4u+6

We add all the numbers together, and all the variables

3u+6

Back to the equation:

-(3u+6)



We get rid of parentheses

-6u-3u-6-6=0

We add all the numbers together, and all the variables

-9u-12=0

We move all terms containing u to the left, all other terms to the right

-9u=12

u=12/-9

u=-1+1/3

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