2(v-1)=4v+6-2(-3v-2)

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Solution for 2(v-1)=4v+6-2(-3v-2) equation: 



2(v-1)=4v+6-2(-3v-2)

We move all terms to the left:

2(v-1)-(4v+6-2(-3v-2))=0

We multiply parentheses

2v-(4v+6-2(-3v-2))-2=0



We calculate terms in parentheses: -(4v+6-2(-3v-2)), so:

4v+6-2(-3v-2)

determiningTheFunctionDomain
4v-2(-3v-2)+6

We multiply parentheses

4v+6v+4+6

We add all the numbers together, and all the variables

10v+10

Back to the equation:

-(10v+10)



We get rid of parentheses

2v-10v-10-2=0

We add all the numbers together, and all the variables

-8v-12=0

We move all terms containing v to the left, all other terms to the right

-8v=12

v=12/-8

v=-1+1/2

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