-3(v+4)=v-6+2(7v+1)

Solution for -3(v+4)=v-6+2(7v+1) equation:

-3(v+4)=v-6+2(7v+1)

We move all terms to the left:

-3(v+4)-(v-6+2(7v+1))=0

We multiply parentheses

-3v-(v-6+2(7v+1))-12=0


We calculate terms in parentheses: -(v-6+2(7v+1)), so:

v-6+2(7v+1)

determiningTheFunctionDomain
v+2(7v+1)-6

We multiply parentheses

v+14v+2-6

We add all the numbers together, and all the variables

15v-4

Back to the equation:

-(15v-4)


We get rid of parentheses

-3v-15v+4-12=0

We add all the numbers together, and all the variables

-18v-8=0

We move all terms containing v to the left, all other terms to the right

-18v=8

v=8/-18

v=-4/9