2(v+8)=-2(6v-5)+2v

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Solution for 2(v+8)=-2(6v-5)+2v equation: 



2(v+8)=-2(6v-5)+2v

We move all terms to the left:

2(v+8)-(-2(6v-5)+2v)=0

We multiply parentheses

2v-(-2(6v-5)+2v)+16=0



We calculate terms in parentheses: -(-2(6v-5)+2v), so:

-2(6v-5)+2v

We add all the numbers together, and all the variables

2v-2(6v-5)

We multiply parentheses

2v-12v+10

We add all the numbers together, and all the variables

-10v+10

Back to the equation:

-(-10v+10)



We get rid of parentheses

2v+10v-10+16=0

We add all the numbers together, and all the variables

12v+6=0

We move all terms containing v to the left, all other terms to the right

12v=-6

v=-6/12

v=-1/2

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