-3(-3y+2)-y=2(y-5)-4

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Solution for -3(-3y+2)-y=2(y-5)-4 equation: 



-3(-3y+2)-y=2(y-5)-4

We move all terms to the left:

-3(-3y+2)-y-(2(y-5)-4)=0

We add all the numbers together, and all the variables

-1y-3(-3y+2)-(2(y-5)-4)=0

We multiply parentheses

-1y+9y-(2(y-5)-4)-6=0



We calculate terms in parentheses: -(2(y-5)-4), so:

2(y-5)-4

We multiply parentheses

2y-10-4

We add all the numbers together, and all the variables

2y-14

Back to the equation:

-(2y-14)



We add all the numbers together, and all the variables

8y-(2y-14)-6=0

We get rid of parentheses

8y-2y+14-6=0

We add all the numbers together, and all the variables

6y+8=0

We move all terms containing y to the left, all other terms to the right

6y=-8

y=-8/6

y=-1+1/3

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