2(v+4)+2(1+7v)=58

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Solution for 2(v+4)+2(1+7v)=58 equation: 



2(v+4)+2(1+7v)=58

We move all terms to the left:

2(v+4)+2(1+7v)-(58)=0

We add all the numbers together, and all the variables

2(v+4)+2(7v+1)-58=0

We multiply parentheses

2v+14v+8+2-58=0

We add all the numbers together, and all the variables

16v-48=0

We move all terms containing v to the left, all other terms to the right

16v=48

v=48/16

v=3

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