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6(x-4)+3(x+3)-5(2x-5)=8x+3(2x-4)
We move all terms to the left:
6(x-4)+3(x+3)-5(2x-5)-(8x+3(2x-4))=0
We multiply parentheses
6x+3x-10x-(8x+3(2x-4))-24+9+25=0
We calculate terms in parentheses: -(8x+3(2x-4)), so:We add all the numbers together, and all the variables
8x+3(2x-4)
We multiply parentheses
8x+6x-12
We add all the numbers together, and all the variables
14x-12
Back to the equation:
-(14x-12)
-1x-(14x-12)+10=0
We get rid of parentheses
-1x-14x+12+10=0
We add all the numbers together, and all the variables
-15x+22=0
We move all terms containing x to the left, all other terms to the right
-15x=-22
x=-22/-15
x=1+7/15
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