2(v+3)(-v-9)=0

Solution for 2(v+3)(-v-9)=0 equation:

2(v+3)(-v-9)=0

We add all the numbers together, and all the variables

2(v+3)(-1v-9)=0

We multiply parentheses ..

2(-1v^2-9v-3v-27)=0

We multiply parentheses

-2v^2-18v-6v-54=0

We add all the numbers together, and all the variables

-2v^2-24v-54=0

a = -2; b = -24; c = -54;
Δ = b2-4ac
Δ = -242-4·(-2)·(-54)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12}{2*-2}=\frac{12}{-4}
=-3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12}{2*-2}=\frac{36}{-4}
=-9
$