2(u-5)=-5u+32

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Solution for 2(u-5)=-5u+32 equation: 



2(u-5)=-5u+32

We move all terms to the left:

2(u-5)-(-5u+32)=0

We multiply parentheses

2u-(-5u+32)-10=0

We get rid of parentheses

2u+5u-32-10=0

We add all the numbers together, and all the variables

7u-42=0

We move all terms containing u to the left, all other terms to the right

7u=42

u=42/7

u=6

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