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6(x-3)+3x=5+8(x-4)
We move all terms to the left:
6(x-3)+3x-(5+8(x-4))=0
We add all the numbers together, and all the variables
3x+6(x-3)-(5+8(x-4))=0
We multiply parentheses
3x+6x-(5+8(x-4))-18=0
We calculate terms in parentheses: -(5+8(x-4)), so:We add all the numbers together, and all the variables
5+8(x-4)
determiningTheFunctionDomain 8(x-4)+5
We multiply parentheses
8x-32+5
We add all the numbers together, and all the variables
8x-27
Back to the equation:
-(8x-27)
9x-(8x-27)-18=0
We get rid of parentheses
9x-8x+27-18=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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