2(u-3)=8u+1-3(-2u-1)

Solution for 2(u-3)=8u+1-3(-2u-1) equation:

2(u-3)=8u+1-3(-2u-1)

We move all terms to the left:

2(u-3)-(8u+1-3(-2u-1))=0

We multiply parentheses

2u-(8u+1-3(-2u-1))-6=0


We calculate terms in parentheses: -(8u+1-3(-2u-1)), so:

8u+1-3(-2u-1)

determiningTheFunctionDomain
8u-3(-2u-1)+1

We multiply parentheses

8u+6u+3+1

We add all the numbers together, and all the variables

14u+4

Back to the equation:

-(14u+4)


We get rid of parentheses

2u-14u-4-6=0

We add all the numbers together, and all the variables

-12u-10=0

We move all terms containing u to the left, all other terms to the right

-12u=10

u=10/-12

u=-5/6