2(64-7x)=48-4x

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Solution for 2(64-7x)=48-4x equation: 



2(64-7x)=48-4x

We move all terms to the left:

2(64-7x)-(48-4x)=0

We add all the numbers together, and all the variables

2(-7x+64)-(-4x+48)=0

We multiply parentheses

-14x-(-4x+48)+128=0

We get rid of parentheses

-14x+4x-48+128=0

We add all the numbers together, and all the variables

-10x+80=0

We move all terms containing x to the left, all other terms to the right

-10x=-80

x=-80/-10

x=+8

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