2(u-2)=7u+7-2(2u-2)

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Solution for 2(u-2)=7u+7-2(2u-2) equation: 



2(u-2)=7u+7-2(2u-2)

We move all terms to the left:

2(u-2)-(7u+7-2(2u-2))=0

We multiply parentheses

2u-(7u+7-2(2u-2))-4=0



We calculate terms in parentheses: -(7u+7-2(2u-2)), so:

7u+7-2(2u-2)

determiningTheFunctionDomain
7u-2(2u-2)+7

We multiply parentheses

7u-4u+4+7

We add all the numbers together, and all the variables

3u+11

Back to the equation:

-(3u+11)



We get rid of parentheses

2u-3u-11-4=0

We add all the numbers together, and all the variables

-1u-15=0

We move all terms containing u to the left, all other terms to the right

-u=15

u=15/-1

u=-15

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