19=3(y+4)+4y

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Solution for 19=3(y+4)+4y equation: 



19=3(y+4)+4y

We move all terms to the left:

19-(3(y+4)+4y)=0



We calculate terms in parentheses: -(3(y+4)+4y), so:

3(y+4)+4y

We add all the numbers together, and all the variables

4y+3(y+4)

We multiply parentheses

4y+3y+12

We add all the numbers together, and all the variables

7y+12

Back to the equation:

-(7y+12)



We get rid of parentheses

-7y-12+19=0

We add all the numbers together, and all the variables

-7y+7=0

We move all terms containing y to the left, all other terms to the right

-7y=-7

y=-7/-7

y=1

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