2(u-1)=2u+2-3(-4u-4)

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Solution for 2(u-1)=2u+2-3(-4u-4) equation:



2(u-1)=2u+2-3(-4u-4)
We move all terms to the left:
2(u-1)-(2u+2-3(-4u-4))=0
We multiply parentheses
2u-(2u+2-3(-4u-4))-2=0
We calculate terms in parentheses: -(2u+2-3(-4u-4)), so:
2u+2-3(-4u-4)
determiningTheFunctionDomain 2u-3(-4u-4)+2
We multiply parentheses
2u+12u+12+2
We add all the numbers together, and all the variables
14u+14
Back to the equation:
-(14u+14)
We get rid of parentheses
2u-14u-14-2=0
We add all the numbers together, and all the variables
-12u-16=0
We move all terms containing u to the left, all other terms to the right
-12u=16
u=16/-12
u=-1+1/3

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