2(u+3)=3(1-u)+23u

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Solution for 2(u+3)=3(1-u)+23u equation: 



2(u+3)=3(1-u)+23u

We move all terms to the left:

2(u+3)-(3(1-u)+23u)=0

We add all the numbers together, and all the variables

2(u+3)-(3(-1u+1)+23u)=0

We multiply parentheses

2u-(3(-1u+1)+23u)+6=0



We calculate terms in parentheses: -(3(-1u+1)+23u), so:

3(-1u+1)+23u

We add all the numbers together, and all the variables

23u+3(-1u+1)

We multiply parentheses

23u-3u+3

We add all the numbers together, and all the variables

20u+3

Back to the equation:

-(20u+3)



We get rid of parentheses

2u-20u-3+6=0

We add all the numbers together, and all the variables

-18u+3=0

We move all terms containing u to the left, all other terms to the right

-18u=-3

u=-3/-18

u=1/6

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