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5(x-11)/3=3(1+x)/2
We move all terms to the left:
5(x-11)/3-(3(1+x)/2)=0
We add all the numbers together, and all the variables
5(x-11)/3-(3(x+1)/2)=0
We calculate fractions
5x/()+(-(3(x+1)*3)/()=0
We calculate terms in parentheses: +(-(3(x+1)*3)/(), so:We get rid of parentheses
-(3(x+1)*3)/(
We multiply all the terms by the denominator
-(3(x+1)*3)
We calculate terms in parentheses: -(3(x+1)*3), so:We get rid of parentheses
3(x+1)*3
We multiply parentheses
9x+9
Back to the equation:
-(9x+9)
-9x-9
Back to the equation:
+(-9x-9)
5x/()-9x-9=0
We multiply all the terms by the denominator
5x-9x*()-9*()=0
We add all the numbers together, and all the variables
5x-9x*()=0
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