2(u+3)=3(1-u)+23.

Solution for 2(u+3)=3(1-u)+23. equation:

2(u+3)=3(1-u)+23.

We move all terms to the left:

2(u+3)-(3(1-u)+23.)=0

We add all the numbers together, and all the variables

2(u+3)-(3(-1u+1)+23.)=0

We multiply parentheses

2u-(3(-1u+1)+23.)+6=0


We calculate terms in parentheses: -(3(-1u+1)+23.), so:

3(-1u+1)+23.

We add all the numbers together, and all the variables

3(-1u+1)+23

We multiply parentheses

-3u+3+23

We add all the numbers together, and all the variables

-3u+26

Back to the equation:

-(-3u+26)


We get rid of parentheses

2u+3u-26+6=0

We add all the numbers together, and all the variables

5u-20=0

We move all terms containing u to the left, all other terms to the right

5u=20

u=20/5

u=4