-4(1+3d)=28

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Solution for -4(1+3d)=28 equation: 



-4(1+3d)=28

We move all terms to the left:

-4(1+3d)-(28)=0

We add all the numbers together, and all the variables

-4(3d+1)-28=0

We multiply parentheses

-12d-4-28=0

We add all the numbers together, and all the variables

-12d-32=0

We move all terms containing d to the left, all other terms to the right

-12d=32

d=32/-12

d=-2+2/3

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