2(u+3)=-4u-12

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Solution for 2(u+3)=-4u-12 equation:



2(u+3)=-4u-12
We move all terms to the left:
2(u+3)-(-4u-12)=0
We multiply parentheses
2u-(-4u-12)+6=0
We get rid of parentheses
2u+4u+12+6=0
We add all the numbers together, and all the variables
6u+18=0
We move all terms containing u to the left, all other terms to the right
6u=-18
u=-18/6
u=-3

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