8(1+2x)=28+4x

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Solution for 8(1+2x)=28+4x equation: 



8(1+2x)=28+4x

We move all terms to the left:

8(1+2x)-(28+4x)=0

We add all the numbers together, and all the variables

8(2x+1)-(4x+28)=0

We multiply parentheses

16x-(4x+28)+8=0

We get rid of parentheses

16x-4x-28+8=0

We add all the numbers together, and all the variables

12x-20=0

We move all terms containing x to the left, all other terms to the right

12x=20

x=20/12

x=1+2/3

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