2(u+3)+u=2(u-1)+3

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Solution for 2(u+3)+u=2(u-1)+3 equation: 



2(u+3)+u=2(u-1)+3

We move all terms to the left:

2(u+3)+u-(2(u-1)+3)=0

We add all the numbers together, and all the variables

u+2(u+3)-(2(u-1)+3)=0

We multiply parentheses

u+2u-(2(u-1)+3)+6=0



We calculate terms in parentheses: -(2(u-1)+3), so:

2(u-1)+3

We multiply parentheses

2u-2+3

We add all the numbers together, and all the variables

2u+1

Back to the equation:

-(2u+1)



We add all the numbers together, and all the variables

3u-(2u+1)+6=0

We get rid of parentheses

3u-2u-1+6=0

We add all the numbers together, and all the variables

u+5=0

We move all terms containing u to the left, all other terms to the right

u=-5

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