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3(x-3)+9=2x+15
We move all terms to the left:
3(x-3)+9-(2x+15)=0
We multiply parentheses
3x-(2x+15)-9+9=0
We get rid of parentheses
3x-2x-15-9+9=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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