2(u+1)+4u=3(2y-1)+8

Solution for 2(u+1)+4u=3(2y-1)+8 equation:

Simplifying
2(u + 1) + 4u = 3(2y + -1) + 8

Reorder the terms:
2(1 + u) + 4u = 3(2y + -1) + 8
(1 * 2 + u * 2) + 4u = 3(2y + -1) + 8
(2 + 2u) + 4u = 3(2y + -1) + 8

Combine like terms: 2u + 4u = 6u
2 + 6u = 3(2y + -1) + 8

Reorder the terms:
2 + 6u = 3(-1 + 2y) + 8
2 + 6u = (-1 * 3 + 2y * 3) + 8
2 + 6u = (-3 + 6y) + 8

Reorder the terms:
2 + 6u = -3 + 8 + 6y

Combine like terms: -3 + 8 = 5
2 + 6u = 5 + 6y

Solving
2 + 6u = 5 + 6y

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6u = 5 + -2 + 6y

Combine like terms: 2 + -2 = 0
0 + 6u = 5 + -2 + 6y
6u = 5 + -2 + 6y

Combine like terms: 5 + -2 = 3
6u = 3 + 6y

Divide each side by '6'.
u = 0.5 + y

Simplifying
u = 0.5 + y