(1/c)+(1/4)=(1/x)

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Solution for (1/c)+(1/4)=(1/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/c+1/4 = 1/x // - 1/x

1/c-(1/x)+1/4 = 0

1/c-x^-1+1/4 = 0

-1*x^-1 = -(c^-1+1/4) // : -1

x^-1 = c^-1+1/4

-1 < 0

1/(x^1) = c^-1+1/4 // * x^1

1 = x^1*(c^-1+1/4) // : c^-1+1/4

1/(c^-1+1/4) = x^1

x = 1/(c^-1+1/4)

x = 1/(c^-1+1/4)

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