2(t-9)=3(t+3)

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Solution for 2(t-9)=3(t+3) equation: 



2(t-9)=3(t+3)

We move all terms to the left:

2(t-9)-(3(t+3))=0

We multiply parentheses

2t-(3(t+3))-18=0



We calculate terms in parentheses: -(3(t+3)), so:

3(t+3)

We multiply parentheses

3t+9

Back to the equation:

-(3t+9)



We get rid of parentheses

2t-3t-9-18=0

We add all the numbers together, and all the variables

-1t-27=0

We move all terms containing t to the left, all other terms to the right

-t=27

t=27/-1

t=-27

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