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3x^2+2x-7=-4x^2+3x+9
We move all terms to the left:
3x^2+2x-7-(-4x^2+3x+9)=0
We get rid of parentheses
3x^2+4x^2-3x+2x-9-7=0
We add all the numbers together, and all the variables
7x^2-1x-16=0
a = 7; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·7·(-16)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{449}}{2*7}=\frac{1-\sqrt{449}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{449}}{2*7}=\frac{1+\sqrt{449}}{14} $
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