2(t-6)-3(2t-7)=9-5(5t+1)

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Solution for 2(t-6)-3(2t-7)=9-5(5t+1) equation: 



2(t-6)-3(2t-7)=9-5(5t+1)

We move all terms to the left:

2(t-6)-3(2t-7)-(9-5(5t+1))=0

We multiply parentheses

2t-6t-(9-5(5t+1))-12+21=0



We calculate terms in parentheses: -(9-5(5t+1)), so:

9-5(5t+1)

determiningTheFunctionDomain
-5(5t+1)+9

We multiply parentheses

-25t-5+9

We add all the numbers together, and all the variables

-25t+4

Back to the equation:

-(-25t+4)



We add all the numbers together, and all the variables

-4t-(-25t+4)+9=0

We get rid of parentheses

-4t+25t-4+9=0

We add all the numbers together, and all the variables

21t+5=0

We move all terms containing t to the left, all other terms to the right

21t=-5

t=-5/21

t=-5/21

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